SQLize
Online
/
PHPize Online
/
SQLtest Online
A
A
A
Share
Donate
Blog
Popular
Donate
A
A
A
Share
Blog
Popular
SQLize.online is a free online SQL environment for quickly running, experimenting with and sharing code.
You can run your SQL code on top of the most popular RDBMS including MySQL, MariaDB, SQLite, PostgreSQL, Oracle and Microsoft SQL Server.
SQL code:
Upload
Copy
Format
Clear
CREATE TABLE Country ( id NUMBER(10) PRIMARY KEY, name VARCHAR2(50) NOT NULL, capital VARCHAR2(50) NOT NULL ); CREATE TABLE Genre ( id NUMBER(10) PRIMARY KEY, name VARCHAR2(50) NOT NULL ); CREATE TABLE Artist( id NUMBER(10), name VARCHAR2(50) NOT NULL, age NUMBER(3), country_id NUMBER(10), city VARCHAR2(50), FOREIGN KEY (country_id) REFERENCES Country(id) ); ALTER TABLE Artist ADD CONSTRAINT students_id_pk PRIMARY KEY (id); CREATE TABLE Song( id NUMBER(10) PRIMARY KEY, name VARCHAR2(100) NOT NULL, artist_id NUMBER(10), genre_id NUMBER(10), FOREIGN KEY (genre_id) REFERENCES Genre(id), FOREIGN KEY (artist_id) REFERENCES Artist(id) ); INSERT INTO Country (id, name, capital) VALUES (1, 'Italy', 'Rome'); INSERT INTO Country (id, name, capital) VALUES (2, 'Spain', 'Madrid'); INSERT INTO Country (id, name, capital) VALUES (3, 'France', 'Paris'); INSERT INTO Country (id, name, capital) VALUES (4, 'USA', 'Washington D.C'); INSERT INTO Country (id, name, capital) VALUES (5, 'Ireland', 'Dublin'); INSERT INTO Artist (id, name, age, country_id, city) VALUES (1, 'Mos Def', 43, 4, 'New York'); INSERT INTO Artist (id, name, age, country_id, city) VALUES (2, 'Salmo', 40, 1, 'Milan'); INSERT INTO Artist (id, name, age, country_id, city) VALUES (3, 'DNash', 41, 2, 'Valencia'); INSERT INTO Artist (id, name, age, country_id, city) VALUES (4, 'GoldFord', 34, 4, 'Charlotte'); INSERT INTO Artist (id, name, age, country_id, city) VALUES (5, 'Giorgia',46 , 1, 'Rome'); INSERT INTO Artist (id, name, age, country_id, city) VALUES (6, 'Giusy Ferreri', 43, 1, 'Florence'); INSERT INTO Artist (id, name, age, country_id, city) VALUES (7, 'Allen Stone', 33, 4, 'San Jose'); INSERT INTO Artist (id, name, age, country_id, city) VALUES (8, 'Lupe Fiasco', 34, 4, 'Chicago'); INSERT INTO Artist (id, name, age, country_id, city) VALUES (9, 'Can', 54, 4, 'Dallas'); INSERT INTO Genre (id, name) VALUES (1, 'hip-hop'); INSERT INTO Genre (id, name) VALUES (2, 'indie'); INSERT INTO Genre (id, name) VALUES (3, 'pop'); INSERT INTO Genre (id, name) VALUES (4, 'rap'); INSERT INTO Song(id, name, artist_id, genre_id) VALUES (1, 'Che ne so', 2, 4); INSERT INTO Song(id, name, artist_id, genre_id) VALUES (2, 'Hip-hop', 1, 1); INSERT INTO Song(id, name, artist_id, genre_id) VALUES (3, 'Loco', 3, 3); INSERT INTO Song(id, name, artist_id, genre_id) VALUES (4, 'Auditorium', 1, 4); INSERT INTO Song(id, name, artist_id, genre_id) VALUES (5, 'Novembre', 6, 3); INSERT INTO Song(id, name, artist_id, genre_id) VALUES (6, 'Come pensi', 6, 3); INSERT INTO Song(id, name, artist_id, genre_id) VALUES (7, 'Mystery', 7, 3); INSERT INTO Song(id, name, artist_id, genre_id) VALUES (8, 'Memory of you', 7, 3); INSERT INTO Song(id, name, artist_id, genre_id) VALUES (9, 'Strong', 7, 3); Select * from Country; Select * from Artist; Select * from Genre; Select * from Song; Select a.name,a.age, c.name From Artist a, Country C Where a.age>35 and a.country_id = c.id; SELECT * FROM Artist WHERE age = 43; SELECT name FROM Country WHERE name IN ('Italy', 'USA'); SELECT name FROM Genre WHERE id NOT IN (1, 3); SELECT name AS Artist_Name, age FROM Artist ORDER BY age DESC; SELECT name AS Song_Name, genre_id FROM Song ORDER BY name ASC; SELECT * FROM Artist WHERE age > ANY (SELECT age FROM Artist WHERE country_id = 1); SELECT name FROM Artist WHERE age BETWEEN 30 AND 40; SELECT * FROM Song WHERE NOT genre_id = 3; SELECT name AS Country_Name FROM Country WHERE EXISTS ( SELECT 1 FROM Artist WHERE Artist.country_id = Country.id AND Artist.age < 40 ); SELECT c.name AS Country_Name, COUNT(a.id) AS Artist_Count FROM Country c LEFT JOIN Artist a ON c.id = a.country_id WHERE NOT EXISTS ( SELECT 1 FROM Artist WHERE Artist.country_id = c.id ) GROUP BY c.name ORDER BY c.name ASC; SELECT * FROM Song WHERE artist_id IS NULL; SELECT Artist.name AS Artist_Name, Country.name AS Country_Name FROM Artist INNER JOIN Country ON Artist.country_id = Country.id; SELECT Artist.name AS Artist_Name, Country.name AS Country_Name FROM Artist LEFT JOIN Country ON Artist.country_id = Country.id; SELECT Artist.name AS Artist_Name, Country.name AS Country_Name FROM Artist RIGHT JOIN Country ON Artist.country_id = Country.id; SELECT Artist.name AS Artist_Name, Country.name AS Country_Name FROM Artist RIGHT JOIN Country ON Country.id BETWEEN 2 AND 4 AND Artist.country_id = Country.id; SELECT Artist.name AS Artist_Name, Country.name AS Country_Name FROM Artist FULL OUTER JOIN Country ON Artist.country_id = Country.id; SELECT Artist.name AS Artist_Name, Genre.name AS Genre_Name FROM Artist CROSS JOIN Genre; SELECT c.name, COUNT(*) AS Artist_Count FROM Artist a, Country c WHERE a.country_id = c.id GROUP BY c.name; SELECT c.name, COUNT(*) AS Artist_Count FROM Artist a, Country c WHERE a.country_id = c.id GROUP BY c.name HAVING COUNT(*) > 2; SELECT MAX(age) AS Oldest_Artist_Age FROM Artist; SELECT MIN(age) AS Youngest_Artist_Age FROM Artist; SELECT c.name AS Country_Name, g.name AS Genre_Name, COUNT(s.id) AS Total_Songs FROM Country c JOIN Artist a ON c.id = a.country_id JOIN Song s ON a.id = s.artist_id JOIN Genre g ON s.genre_id = g.id WHERE g.name IN ('rap', 'pop') GROUP BY c.name, g.name ORDER BY c.name ASC, g.name ASC; WITH CountrySongCount AS ( SELECT a.country_id, COUNT(s.id) AS Total_Songs FROM Artist a JOIN Song s ON a.id = s.artist_id GROUP BY a.country_id ) SELECT c.name AS Country_Name, csc.Total_Songs FROM Country c LEFT JOIN CountrySongCount csc ON c.id = csc.country_id; WITH ArtistSongCount AS ( SELECT s.artist_id, COUNT(*) AS Song_Count FROM Song s GROUP BY s.artist_id ) SELECT a.name AS Artist_Name, ascc.Song_Count FROM Artist a JOIN ArtistSongCount ascc ON a.id = ascc.artist_id WHERE ascc.Song_Count > 1; WITH ArtistGenres AS ( SELECT artist_id, COUNT(DISTINCT genre_id) AS Genre_Count FROM Song GROUP BY artist_id ), ArtistsByCountry AS ( SELECT a.id AS Artist_ID, a.name AS Artist_Name, c.name AS Country_Name FROM Artist a JOIN Country c ON a.country_id = c.id ) SELECT abc.Artist_Name, abc.Country_Name FROM ArtistsByCountry abc JOIN ArtistGenres ag ON abc.Artist_ID = ag.artist_id WHERE ag.Genre_Count > 1; SELECT c.name, a.name, CONNECT_BY_ISCYCLE AS Is_Cycle FROM Country c JOIN Artist a ON c.id = a.country_id CONNECT BY NOCYCLE PRIOR c.id = a.id START WITH c.id IS NOT NULL; ALTER TABLE Song ADD (release_date DATE); UPDATE Song SET release_date = TO_DATE('2021-01-01', 'YYYY-MM-DD') WHERE id = 1; UPDATE Song SET release_date = TO_DATE('2022-06-15', 'YYYY-MM-DD') WHERE id = 2; UPDATE Song SET release_date = TO_DATE('2023-05-12', 'YYYY-MM-DD') WHERE id = 3; SELECT name, release_date FROM Song WHERE release_date > TO_DATE('2022-06-01', 'YYYY-MM-DD'); ALTER TABLE Artist ADD full_name VARCHAR2(100); UPDATE Artist SET full_name = 'Dante Terrell Smith' WHERE id = 1; UPDATE Artist SET full_name = 'Maurizio Pisciottu' WHERE id = 2; UPDATE Artist SET full_name = 'David Alvarez' WHERE id = 3; UPDATE Artist SET full_name = 'Gregory GoldFord' WHERE id = 4; UPDATE Artist SET full_name = 'Giorgia Todrani' WHERE id = 5; UPDATE Artist SET full_name = 'Giusy Ferreri' WHERE id = 6; UPDATE Artist SET full_name = 'Allen Stone' WHERE id = 7; UPDATE Artist SET full_name = 'Wasalu Muhammad Jaco' WHERE id = 8; UPDATE Artist SET full_name = 'Cem Karaca' WHERE id = 9; SELECT full_name, SUBSTR(full_name, INSTR(full_name, ' ', -1) + 1) AS last_name FROM Artist; SELECT full_name, SUBSTR(full_name, 1, INSTR(full_name, ' ') - 1) AS first_name FROM Artist; SELECT full_name, INSTR(full_name, 'Gold') AS position FROM Artist WHERE INSTR(full_name, 'Gold') > 0; ALTER TABLE Artist ADD first_name VARCHAR2(50); ALTER TABLE Artist ADD last_name VARCHAR2(50); UPDATE Artist SET first_name = SUBSTR(full_name, 1, INSTR(full_name, ' ') - 1); UPDATE Artist SET last_name = SUBSTR(full_name, INSTR(full_name, ' ', -1) + 1); SELECT id, full_name, first_name, last_name FROM Artist; --agr SELECT AVG(age) as avg_age FROM Artist; --analytical SELECT name, age, RANK() OVER (ORDER BY age DESC) AS age_ranks FROM Artist; SELECT name, genre_id, COUNT(*) OVER(PARTITION BY genre_id) AS songs_in_g FROM Song; SELECT name, release_date, FIRST_VALUE(name) OVER (PARTITION BY genre_id ORDER BY release_date ASC) AS first_song, LAST_VALUE(name) OVER (PARTITION BY genre_id ORDER BY release_date ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) AS last_song FROM Song; SELECT song_id,name, artist_id, FIRST_VALUE(name) OVER (PARTITION BY artist_id ORDER BY song_id ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS first_song, LAST_VALUE(name) OVER (PARTITION BY artist_id ORDER BY song_id ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING) AS last_song FROM Song;
SQL
Server:
MariaDB 11.4
MariaDB 11.5
MariaDB 10
MariaDB 10 Sakila (ReadOnly)
MySQL 5.7
MySQL 5.7 Sakila (ReadOnly)
MySQL 8.0
MySQL 8.0 Sakila (ReadOnly)
SQLite 3
SQLite 3 Preloaded
PostgreSQL 10 Bookings (ReadOnly)
PostgreSQL 11
PostgreSQL 12
PostgreSQL 13
PostgreSQL 14
PostgreSQL 15
MS SQL Server 2017
MS SQL Server 2019
MS SQL Server 2022
MS SQL Server 2022 AdventureWorks (ReadOnly)
Firebird 4.0
Firebird 4.0 (Employee)
Oracle Database 19c (HR)
Oracle Database 21c
Oracle Database 23c Free
SOQOL
Version
ER Diagram
Preserve result
Stuck with a problem?
Got Error?
Ask ChatGPT!
Result:
Copy
Clear