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with t as ( select 1 as id from dual union all select 2 as id from dual union all select 3 as id from dual union all select 4 as id from dual union all select 4 as id from dual union all select 5 as id from dual union all select 6 as id from dual union all select 8 as id from dual union all select 10 as id from dual ) Select id, Dense_rank() over (partition by id order by id asc) id_true from t

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