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--user_id, boss_user_id, payment with db as ( select distinct employee_id as user_id, manager_id as boss_user_id, salary as payment from employees ) select avg(employees) from ( select distinct t1.boss_user_id as bossid ,(count(*) over (partition by t1.boss_user_id)) as employees from db t1 left join db t2 on t1.boss_user_id = t2.user_id )

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