SQLize Online / PHPize Online  /  SQLtest Online

A A A
Share      Blog   Popular
Copy Format Clear
SET SESSION group_concat_max_len = 1000000; SELECT rental.rental_date AS "meet_time", cu.store_id AS "store_id", GROUP_CONCAT(cu.last_name, " ", cu.first_name ORDER BY cu.last_name SEPARATOR ', ') AS "customers" FROM customer cu INNER JOIN rental ON cu.customer_id = rental.customer_id INNER JOIN staff ON rental.staff_id = staff.staff_id GROUP BY rental.rental_date, cu.store_id ORDER BY meet_time ASC, store_id ASC;

Stuck with a problem? Got Error? Ask ChatGPT!

Copy Clear
Like the site? Share it!
Have a questions? Ask in our telegram chat!
© 2025 Free Online MySQL 8.0 Sakila (ReadOnly) Playground: Practice & Master SQL Skills | About project | Disclaimer
PHP versions: PHP 5.6, PHP 7.4, PHP 8.0, PHP 8.1, PHP 8.2.13
RDBMS versions: MySQL 5.7, MySQL 5.7 Sakila (ReadOnly), MySQL 8.0, MySQL 8.0 Sakila (ReadOnly), MariaDB 11.5, SQLite 3, SQLite 3 Preloaded, PostgreSQL 10 Bookings (ReadOnly), PostgreSQL 11, PostgreSQL 12, PostgreSQL 13, PostgreSQL 14, PostgreSQL 15, MS SQL Server 2017, MS SQL Server 2019, MS SQL Server 2022, MS SQL Server 2022 AdventureWorks (ReadOnly), Firebird 4.0, Firebird 4.0 (Employee), Oracle Database 19c (HR), Oracle Database 21c, Oracle Database 23c Free, SOQOL