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SELECT json_agg(json_build_object( 'id', f.film_id, 'title', f.title, 'category', c.name )) AS film FROM film f JOIN film_category fc ON f.film_id = fc.film_id JOIN category c ON fc.category_id = c.category_id ORDER BY f.film_id; ; show status like 'Last_query_cost';

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