SQLize Online / PHPize Online  /  SQLtest Online

A A A
Share      Blog   Popular
Copy Format Clear
select a.first_name as first_name, a.last_name as last_name, count(distinct c.category_id) as film_count from actor a join film_actor fa on a.actor_id = fa.actor_id join film f on f.film_id = fa.film_id join film_category fc on fc.film_id = f.film_id join category c on c.category_id = fc.category_id group by first_name, last_name order by film_count desc, last_name
Stuck with a problem? Got Error? Ask ChatGPT!
Copy Clear
Like the site? Share it!
Have a questions? Ask in our telegram chat!
© 2024 Run, Practice, Share: Your Interactive SQL Playground - sqlize.online | About project | Disclaimer
PHP versions: PHP 5.6, PHP 7.4, PHP 8.0, PHP 8.1, PHP 8.2.13
RDBMS versions: MySQL 5.7, MySQL 5.7 Sakila (ReadOnly), MySQL 8.0, MySQL 8.0 Sakila (ReadOnly), MariaDB 10, MariaDB 10 Sakila (ReadOnly), SQLite 3, PostgreSQL 10 Bookings (ReadOnly), PostgreSQL 11, PostgreSQL 12, PostgreSQL 13, PostgreSQL 14, PostgreSQL 15, MS SQL Server 2017, MS SQL Server 2019, MS SQL Server 2022, MS SQL Server 2022 AdventureWorks (ReadOnly), Firebird 4.0, Firebird 4.0 (Employee), Oracle Database 19c (HR), Oracle Database 21c, Oracle Database 23c Free, SOQOL