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with d as ( select customer_id, row_number() over(order by return_date, rental_date) as row_num, rental_date as start_date, return_date as finish_date, lag(return_date, 1) over (order by return_date, rental_date) as prev_return_date from rental where customer_id = 1 order by row_num ) select *, case when d.prev_return_date >= start_date then 0 else 1 end from d;

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