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with custs as( select customer_id,count(rental_id) as rent_ct from rental group by customer_id having count(rental_id) > (select count(rental_id)/count(distinct customer_id) from rental) ) select t1.customer_id, t2.first_name,t2.last_name, t1.rent_ct from custs t1 join customer t2 on t1.customer_id = t2.customer_id; ; show status like 'Last_query_cost';

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