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with t as ( select rental_date, return_date, lag(return_date) over(order by return_date, rental_date) as prv from rental where customer_id = 1 order by return_date, rental_date ) select rental_date, return_date, prv, sum(if(rental_date > prv, 1, 0)) over(order by return_date, rental_date) as p from t

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