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select rental_date, return_date, lag(return_date) over(order by return_date, rental_date) as prv, sum(case when rental_date > lag(return_date) over(order by return_date, rental_date) then 1 else 0 end) over(order by return_date, rental_date) from rental where customer_id = 1 order by return_date, rental_date

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