SQLize Online / PHPize Online  /  SQLtest Online

A A A
Share      Blog   Popular
Copy Format Clear
SET SESSION group_concat_max_len = 1000000;; SELECT r.rental_date AS meet_time, i.store_id, GROUP_CONCAT(CONCAT(c.first_name, ' ', c.last_name) ORDER BY c.last_name SEPARATOR ',') AS customers FROM rental r JOIN inventory i ON r.inventory_id = i.inventory_id JOIN customer c ON r.customer_id = c.customer_id GROUP BY r.rental_date, i.store_id ORDER BY r.rental_date, i.store_id; ; show status like 'Last_query_cost';

Stuck with a problem? Got Error? Ask ChatGPT!

Copy Clear
Like the site? Share it!
Have a questions? Ask in our telegram chat!
© 2025 Free Online MySQL 8.0 Sakila (ReadOnly) Playground: Practice & Master SQL Skills | About project | Disclaimer
PHP versions: PHP 5.6, PHP 7.4, PHP 8.0, PHP 8.1, PHP 8.2.13
RDBMS versions: MySQL 5.7, MySQL 5.7 Sakila (ReadOnly), MySQL 8.0, MySQL 8.0 Sakila (ReadOnly), MariaDB 11.5, SQLite 3, SQLite 3 Preloaded, PostgreSQL 10 Bookings (ReadOnly), PostgreSQL 11, PostgreSQL 12, PostgreSQL 13, PostgreSQL 14, PostgreSQL 15, MS SQL Server 2017, MS SQL Server 2019, MS SQL Server 2022, MS SQL Server 2022 AdventureWorks (ReadOnly), Firebird 4.0, Firebird 4.0 (Employee), Oracle Database 19c (HR), Oracle Database 21c, Oracle Database 23c Free, SOQOL