SET SESSION group_concat_max_len = 1000000;;
select
r.rental_date meet_time
, s.store_id
, group_concat(distinct concat(c.first_name, ' ', c.last_name)
order by c.last_name separator ',') customers
from rental r
inner join customer c using (customer_id)
inner join staff s using (staff_id)
group by 1, 2
having count(distinct r.customer_id) > 1
order by 1, 2
;
show status like 'Last_query_cost';