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select c.last_name, c.first_name, t1.cnt from customer c join ( select r.customer_id, dense_rank() over(order by count(*) desc) as customer_rank, count(*) as cnt from rental r group by r.customer_id ) t1 on c.customer_id = t1.customer_id where t1.customer_rank <= 3 order by t1.cnt desc, c.last_name asc ; show status like 'Last_query_cost';

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