Free Online MySQL 8.0 Sakila (ReadOnly) Playground: Practice & Master SQL Skills

SQL code: Upload Copy Format Clear

SET SESSION group_concat_max_len = 1000000;; SELECT r.rental_date AS meet_time, s.store_id, GROUP_CONCAT(DISTINCT UPPER(CONCAT(c.first_name, ' ', c.last_name)) ORDER BY c.last_name) AS customers FROM rental r JOIN customer c ON r.customer_id = c.customer_id JOIN staff s ON r.staff_id = s.staff_id GROUP BY r.rental_rate, s.store_id HAVING COUNT(*) > 1 ORDER BY meet_time, store_id; ; show status like 'Last_query_cost';

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SQL Result: ( preserve ) Copy Clear

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