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with base as (select rental_date, return_date, row_number() over(order by rental_date, return_date) as rn, lag(return_date, 1) over(order by rental_date, return_date) as prev from rental where customer_id = 1) select *, sum(case when prev >= rental_date then 0 else 1 end) over(partition by rn) from base

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