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select st.store_id, ceil(round(avg(customer_amount), 2)) as avg_customer_payment from (select cu.store_id, cu.customer_id, sum(pa.amount) as customer_amount from payment pa inner join rental re on pa.rental_id = re.rental_id inner join customer cu on re.customer_id = cu.customer_id group by cu.store_id, cu.customer_id ) as customers_sum_amount inner join store st on customers_sum_amount.store_id = st.store_id group by st.store_id order by st.store_id

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