SQLize Online / PHPize Online  /  SQLtest Online

A A A
Share      Blog   Popular
Copy Format Clear
create table loginlog (log_date date, user varchar(64)); insert into loginlog values ('2013-07-08', 'Carl'), ('2013-07-09', 'Mark'), ('2013-07-09', 'Robert'), ('2013-08-09', 'Robert'), ('2013-08-09', 'Saul'), ('2013-09-09', 'Paula'), ('2014-01-09', 'Mark'), ('2014-02-09', 'Robert'); with recursive years(y) as ( select 2015 as y union all select y-1 as y from years where y > 2010 ) select y, user, count(*) from years rigth join loginlog on year(log_date) = y group by y, user;
Stuck with a problem? Got Error? Ask ChatGPT!
Copy Clear
© 2024 SQLize - format run and share SQL queries online | About project | Disclaimer | our telegram chat
VPS servers at the highest possible quality
PHP versions: PHP 5.6, PHP 7.4, PHP 8.0, PHP 8.1, PHP 8.2.13
RDBMS versions: MySQL 5.7, MySQL 5.7 Sakila (ReadOnly), MySQL 8.0, MySQL 8.0 Sakila (ReadOnly), MariaDB 10, MariaDB 10 Sakila (ReadOnly), SQLite 3, PostgreSQL 10 Bookings (ReadOnly), PostgreSQL 11, PostgreSQL 12, PostgreSQL 13, PostgreSQL 14, PostgreSQL 15, MS SQL Server 2017, MS SQL Server 2019, MS SQL Server 2022, Firebird 4.0, Firebird 4.0 (Employee), Oracle Database 19c (HR), Oracle Database 21c, Oracle Database 23c Free, SOQOL