SQLize Online / PHPize Online  /  SQLtest Online

A A A
Share      Blog   Popular
Copy Format Clear
SELECT customer_id, date(min(payment_date)) first_payment_date, date(max(payment_date)) last_payment_date, sum(amount) total_paid FROM payment GROUP BY customer_id ORDER BY total_paid DESC, customer_id ASC; SELECT DISTINCT customer_id, DATE(FIRST_VALUE(payment_date) OVER (PARTITION BY customer_id ORDER BY payment_date)) AS first_payment_date, DATE(FIRST_VALUE(payment_date) OVER (PARTITION BY customer_id ORDER BY payment_date DESC)) AS last_payment_date, SUM(amount) OVER (PARTITION BY customer_id) AS total_paid FROM payment ORDER BY total_paid DESC, customer_id;

Stuck with a problem? Got Error? Ask ChatGPT!

Copy Clear
Like the site? Share it!
Have a questions? Ask in our telegram chat!
© 2024 Free Online MySQL 5.7 Sakila (ReadOnly) Playground: Practice & Master SQL Skills | About project | Disclaimer
PHP versions: PHP 5.6, PHP 7.4, PHP 8.0, PHP 8.1, PHP 8.2.13
RDBMS versions: MariaDB 11.4, MariaDB 11.5, MariaDB 10, MariaDB 10 Sakila (ReadOnly), MySQL 5.7, MySQL 5.7 Sakila (ReadOnly), MySQL 8.0, MySQL 8.0 Sakila (ReadOnly), SQLite 3, SQLite 3 Preloaded, PostgreSQL 10 Bookings (ReadOnly), PostgreSQL 11, PostgreSQL 12, PostgreSQL 13, PostgreSQL 14, PostgreSQL 15, MS SQL Server 2017, MS SQL Server 2019, MS SQL Server 2022, MS SQL Server 2022 AdventureWorks (ReadOnly), Firebird 4.0, Firebird 4.0 (Employee), Oracle Database 19c (HR), Oracle Database 21c, Oracle Database 23c Free, SOQOL