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create table news ( id int, user_id int ); insert into news values (1, 1), (2, 1), (3, 2), (4,3); create table user_news ( news_id int, user_id int ); insert into user_news values (1, 1), (4,3); select * from news where not exists ( select 1 from user_news where user_news.news_id = news.id and user_news.user_id = news.user_id );

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